1/4"= .25"
ok.. radius times radius time pi..
.125x.125x(pi)=0.04908 square inches...
3/16"= wait.... eep... the math in my head just glitched really badly. I was thinking 3/8" *crawls back into his hole*
Isn't that what the clippard rams are? not the minirams..... the fittings look the right size. if that's true... then it has 2x the piston aera.
3/8" gives us .1sq inch of aera... Doubble what the ram in the calculations gave us.. so we get doubble the force for the same pressure.
ok.. radius times radius time pi..
.125x.125x(pi)=0.04908 square inches...
3/16"= wait.... eep... the math in my head just glitched really badly. I was thinking 3/8" *crawls back into his hole*
Isn't that what the clippard rams are? not the minirams..... the fittings look the right size. if that's true... then it has 2x the piston aera.
3/8" gives us .1sq inch of aera... Doubble what the ram in the calculations gave us.. so we get doubble the force for the same pressure.


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