booyah
10-05-2001, 07:55 PM
situation,
a runner sprinting across the feild, you at a decent distance putting a line of paint where you KNOW he is going to run, say at a 90 degree angle to his run... i got bored and did some math for all of you!!!
lets say your shooting 10 balls a second, and your gun is running 280 fps velocity (now i am assuming this is done in a vaccum cause i wasnt that bored to try to figure air resistance) how fast does that person have to be running to run through that rain of paint to have a chance of coming out okay?
heres my math, correct me if you find mistakes!!!
i converted many of these numbers to meters and such so bear with me
280fps is about 85meters/second (Mps)
1meter is about 39.25 inches
first off
10balls a second means one ball every .1 second. that means that your paintballs are spaced at a distance from each other of .1 * 280 or 28 feet (8.5 meters)
heres where individual sizes come into affect.
i'll use my meassurements on this. we are assuming the player is running perpendicular to the stream of paint (90 degrees) so the width of their chest and thickness is very important here.
the number that actually matters is a vector since they could get hit in the chest or the side. its a simple euclidien triangle
side
------|
\_____|
_\____|chest width
__\___|
___\__|
area\_|
that \|
matters
Mind you I am a bigger than average guy so this will skew the calculations slightly
Accross my shoulders i am 24 inches (2ft) wide and at my thickest (mid chest) i am 11 inches thick.
now we thank do a good ol a^2+b^2=c^2 or 24^2(576) + 11^2(121)= c^2 (697)
so the area for impact is 26.4 inches or 26 for easy math
so we have the area that can be hit (.66 meters) the time to pass the distance (.1 seconds) so how fast would i have to be moving to keep from being hit?
good ol velocity = distance/time
v=d/t v=.66/.1 or about 6.6Meters/second or almost 15miles per hour
pretty fast run that i dont think i can do....
thought this would be fun for some of you and my friday night plans were canceled....
update:
after some extra thinking, i think i missed something here, the way i figured this out, the velocity of the paint doesnt matter.... you would still have that .1 seconds to clear the .66 meters in sicne its th delay between balls....
hmmm please correct me if i'm wrong, its been years since i've done real physics....
-Booyah
a runner sprinting across the feild, you at a decent distance putting a line of paint where you KNOW he is going to run, say at a 90 degree angle to his run... i got bored and did some math for all of you!!!
lets say your shooting 10 balls a second, and your gun is running 280 fps velocity (now i am assuming this is done in a vaccum cause i wasnt that bored to try to figure air resistance) how fast does that person have to be running to run through that rain of paint to have a chance of coming out okay?
heres my math, correct me if you find mistakes!!!
i converted many of these numbers to meters and such so bear with me
280fps is about 85meters/second (Mps)
1meter is about 39.25 inches
first off
10balls a second means one ball every .1 second. that means that your paintballs are spaced at a distance from each other of .1 * 280 or 28 feet (8.5 meters)
heres where individual sizes come into affect.
i'll use my meassurements on this. we are assuming the player is running perpendicular to the stream of paint (90 degrees) so the width of their chest and thickness is very important here.
the number that actually matters is a vector since they could get hit in the chest or the side. its a simple euclidien triangle
side
------|
\_____|
_\____|chest width
__\___|
___\__|
area\_|
that \|
matters
Mind you I am a bigger than average guy so this will skew the calculations slightly
Accross my shoulders i am 24 inches (2ft) wide and at my thickest (mid chest) i am 11 inches thick.
now we thank do a good ol a^2+b^2=c^2 or 24^2(576) + 11^2(121)= c^2 (697)
so the area for impact is 26.4 inches or 26 for easy math
so we have the area that can be hit (.66 meters) the time to pass the distance (.1 seconds) so how fast would i have to be moving to keep from being hit?
good ol velocity = distance/time
v=d/t v=.66/.1 or about 6.6Meters/second or almost 15miles per hour
pretty fast run that i dont think i can do....
thought this would be fun for some of you and my friday night plans were canceled....
update:
after some extra thinking, i think i missed something here, the way i figured this out, the velocity of the paint doesnt matter.... you would still have that .1 seconds to clear the .66 meters in sicne its th delay between balls....
hmmm please correct me if i'm wrong, its been years since i've done real physics....
-Booyah