"N2 is quieter?" testing

[athomas]

If the number of molecules is the same. I stand corrected. I don't know what train of thought I was on with that one. The amount of energy contained is greater with CO2 though. This due to the greater mass at the same volume of gas.

KE = 1/2(m)(v^2)
(m1)(v1)=(m2)(v2) where v= volume and m = mass. (Boyles Law)

Now, either both gases have the same mass, or there are more molecules with less mass in the same volume as the molecules with the higher mass at a given pressure to do the same work.

[LoveMyMagMoreThanYou]

Originally posted by athomas
KE = 1/2(m)(v^2)
(m1)(v1^2)=(m2)(v2^2) where v= volume and m = mass.

Now, either both gases have the same mass, or there are more molecules with less mass in the same volume as the molecules with the higher mass at a given pressure to do the same work.

The "v" in your KE formula is velocity and not volume. Therefore the previous argument is still valid: KEs can be the same with the more massive molecules having lower velocities.

Be careful not to mix your formulas!

[TRIAD]

Originally posted by TRIAD

At any given temperature, all substances have the same average KE (temperature being a relative measure of the average kinetic energy of a substance). Thus, while one gas molecule might be more massive (let's compare a molecule of Ar to a molecule of N2), the one that is more massive will also be traveling at a lower velocity. (KE=(1/2)M Vsquared).
So, a mole of Ar gas and a mole of N2 gas will have (essentially) the same kinetic energy (considering they have the same average kinetic energy, and you have a specific amount of each). When you fill a tank wwith Ar, since Ar has a molecular mass of 18, the molecules have, on average, a higher velocity than molecules of molecular nitrogen (molecular mass of 28.0134). Molecular weight is therefore a moot point when dealing with the propulsion of a paintball (as far as I can see), because the average KE of each molecule of gas is still the same.

[LoveMyMagMoreThanYou]

TRIAD, if you thought that I was trying to refute your arguement, I'm sorry. athomas was the one I was refuting. Your arguement looks sound.

[TRIAD]

Didn't think you were, sorry if it looked that way. I was building on your correction of his units, further explaining the whole equation and how it applies here.

[LoveMyMagMoreThanYou]

I just wanted to make sure that my viewpoint was clear. Thanks TRIAD

[TRIAD]

http://www.automags.org/forums/showthread.php?s=&threadid=21839&pagenumber=2

The same sort of discussion is going on in this thread. I was wrong in using the KE=1/2MV(squared) equation, because not all the KE the gas molecule possesses will be passed on to the paintball. After discussion with my physics teacher, I did however come to the conclusion that a different gas will in no way affect how the paintball is propelled. The equations he used to show this I put in that thread.