Psuedo Code Problem!!! Urgent!!!

[pharcyde]

[pharcyde]

ok i may have solved the first two, but i really need help on the last one.

[MagMan5446]

Yeah, I don't know anything about what you're talking about, but I was wondering about your name. Pharcyde as in the group? I just listened to their remix of Doin' Time, it rocks.

[pharcyde]

yeah i got the name from the group but, i don't listen to there music. i just needed a name, and my brother had a pharcyde cd laying around.

[alf]

arrays

can you put the values into an array?

do you have icq? im 19631307, if you do

i know....read it left to right, keep concatenating it into a string...(the highest order digit will be put in first)

then process the string first 0/1 gets the value of 2 to the 0th power (= 1), second 0/1 gets 2 to the 1st power (=2), third 0/1 gets 2 to the 2nd power (=4), just accumulate it till you reach the end of the string

will that work for ya?

-alf

[pharcyde]

no cant use arrays, i'll read over what you wrote now

[Miscue]

a.

1.

(turn the date into YYYYMMDD format. YYYY carries most weight, so it is put in front. In this way you can directly compare it to other dates using < > =, etc.)

todayDate = yearToday * 1000 + (monthToday) * 100 + dayToday

otherDate = yearOther * 1000 + (monthOther) * 100 + dayOther

if todayDate == otherDate
present
if todayDate > otherDate
past
else
future

2.
(Easier to understand, but not as efficient and harder to code)

if yearToday > yearOther
past
else if yearToday < yearOther
future
else
if monthToday > monthOther...

pattern continues...

b.


main

repeat until end of file
read letter
if y read in
yFoundProcedure
end if
end repeat

end main

yFoundProcedure
read letter
if end of file, quit
else
if y read in
yFoundProcedure (call itself, takes the 'yyy' case into consideration)
else if . or , or (space) read in
increment wordsEndInY
end if
end yFoundProcedure

c. (are you sure it's left-most digit? or right?)

The left-most digits is way harder... I'm working on it now...

[Miscue]

Re: arrays

Originally posted by alf
can you put the values into an array?


i know....read it left to right, keep concatenating it into a string...

A string is an array of characters. If he can't use an array, he can't use a string.

Going right to left there is a super simple formula... left to right... a pain. I can't see why your teacher would ask you to do it that way...

[pharcyde]

left most for sure

[alf]

i think i got it...miscue, whatcha think?

alright...
i wont do the pseudo code for you but here is the theory

for every new digit, you will add 1 or 0 (since it is the least significant bit)...before you do that, you have to shift the others left...do to this, just multiply by 2

(do some examples)

111=7
promote 111 to 1110 and that is 14, then add 1 or 0

11011 = 27
promote (shift left) to 110110 and that is 54, then add 0 or 1

will that work?

[Miscue]

c. Here goes...

main
getBinary
convertToDec
end main

begin getBinary
digit=0
accumulator=0
repeat until end
accumulator = accumulator * 10 // move digit over
read digit
if not end
accumulator = accumulator + digit // tack on next dig
end if
digit = digit+1
end repeat
end getBinary

begin convertToDec
currExp = 0
decimalAnswer = 0
repeat until digit = 0
decimalAnswer = decimalAnswer + (accumulator modulo 10) * 2^(currExp)
digit = digit - 1
currExp = currExp + 1
accumulator = accumulator div 10
end repeat
end convertToDec


I did not double check this for three reasons.... It's probably right... close enough for pseudocode... and it does you no good if I just give you the answer and you don't understand it. You need to go through it and see how it works. If you catch an error, great.

[Miscue]

Dammit alf. That's the easy way.


accumulator = 0
repeat until end
accumulator = accumulator * 2
readDigit
accumulator = accumulator + readDigit
end repeat

[alf]

oops

lol

sorry miscue!

what line of work are you in anyway?

[pharcyde]

thanks guys, i'll have to go over all this and figure out what the heck you typed.

[Miscue]

I take pictures of people and print them out onto school ID cards for $7/hour.