Physics Question

[jwyke]

I have two questions that I have been pondering.

First, Given the acceleration due to gravity is 9.8m/s^2, how long would it take a paintball dropped from 2meters to hit the ground? I am more interested in how to solve this than in what the answer is.

Second. Given that a paintball accelerates from 0ft/s to 285ft/s within the length of the barrel (say 6 inches), what is the acceleration of the paintball?

Any help would be appreciated.

[e mag]

acceleration from rest to the end of the barrel is about 55000fps, im not sure about how long it takes if you drop a paintball though.

[jwyke]

Cool, thanks for the answer to one. How did you caclulate that number?

[e mag]

i forget all the equations, look here http://www.automags.org/forums/showt...threadid=51079

[jwyke]

That math from Joel Hoyt in the thread you sent me was exactly what I was looking for, thank you.

I was even able to answer my first question based on equations he used.

[71 LS6]

1. D = Vi*T + .5 A*(T)^2

D = distance (2 meters)

Vi = initial velocity (0 meters/second if dropped from rest)

T = time

A = acceleration (9.81 meters/second^2)

so,

2 = 0*T + .5 (9.81)*(T)^2

2 = 4.9*(T^2)

.408 = T^2

.639 seconds = T



2. Vf^2 = Vi^2 + 2AD

Vf = final velocity

D = .5 (6 inches = .5 feet)

285^2 = 0^2 + 2A(.5)

81225 = 2A(.5)

81225 feet/seconds^s = A


There ya go, I think those are right

Let me know if you need some more of the base equations, they're all right here in the reference table

EDIT: oops, didnt see the post above me.

[Kevmaster]

yep...they're right