find the following trigonometric expression as an algebraic expression in terms of x show all work
sin (2arcsinx)-cos(2arccosx)
sin (2arcsinx)-cos(2arccosx)
-
- AGD "Yea well our intention is to
take over the world....one country at a time..... :)" - Rt Pro X Valved Warp fed My Rtp
- Props to Echo for the sig
- AGD "Yea well our intention is to
-
i am doign sign and cosign now. If you have a graphign calculator you should use that. I don't quite understand the problem you are trying to solve.I knew not what I did but am now edumacated -
it wants an algebraic expression simplified i think cause after im suppose to plug the answer into x to solve sin(2arcsinx) = cos(2arccosx)- AGD "Yea well our intention is to
take over the world....one country at a time..... :)" - Rt Pro X Valved Warp fed My Rtp
- Props to Echo for the sig
Comment
- AGD "Yea well our intention is to
-
sin (2arcsinx)-cos(2arccosx)
Haven't done strait trig in a while, so I can't remember what to do with the 2's, but the sin of the arcsin of something cancels. I.E. sin(arcsinX)=X. The problem wants you to get rid of the sines and cosines and all. Since there's no = sign I don't think you need to substitute. Just get rid of the 2's however you can and you can just cancel the trig parts. I think this is right. I know it works with log properties, but this could be different.
My feedback thread
AIM-bertmcmahan
My email:[email protected]
Good traders: richie,Roguefactor,moufo48,845,brtncstm160,vf-xx
Mags don't shoot darts... they shoot nails.
I used to be bertmcmahan, that I did.Comment
-
Re: Need Math Help
find the following trigonometric expression as an algebraic expression in terms of x show all work
sin (2arcsinx)-cos(2arccosx)
sin (2arcsinx)-cos(2arccosx) = ? doesn't it have to equal something? If you got rid of the 2s, it would be x-x. I think the 2 messes it up thoughComment
-
It's an expression, not an equation, so I'm pretty sure it doesn't have to equal something. The 2's make it do something weird, and I can't remember how to get rid of them.
My feedback threadAIM-bertmcmahan
My email:[email protected]
Good traders: richie,Roguefactor,moufo48,845,brtncstm160,vf-xx
Mags don't shoot darts... they shoot nails.
I used to be bertmcmahan, that I did.Comment
-
The best I can do is:
cos(2*arccos(x)) = 2*x^2 - 1
and
sin(2*arcsin(x)) = 2*x*sqrt(1 - x^2)
The first comes from the trig identity:
cos(2y) = 2*cos^2(y) - 1
The second comes from the trig identity:
sin(2y) = 2*sin(y)cos(y), therefore
sin(2*arcsin(x)) = 2*x*cos(arcsin(x))
Let y = ArcSin(x). We seek Cos(y). Then
Sin(y) = x
1 - (Sin(y))^2 = 1 - x^2
(Cos(y))^2 = 1 - x^2
Cos(y) = sqrt(1 - x^2)
I got that last part from:
http://mathforum.org/epigone/alt.mat...axrimwo/87fojb[email protected]Last edited by deadeye9; 03-29-2004, 06:27 PM.Comment
-
wow glad im still in 9th grade mathComment
-
wow glad im still in 9th grade math
Comment
Comment