monomial factors. me = ?

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  • wanna-b-ballin'
    Pump Player
    • Jan 2005
    • 1380

    #1

    monomial factors. me = ?

    alright, so my math teacher just assigned me some crap, and did a real crappy job at giving us notes about it. looking in my book didn't really help me. so i came here.

    "find the greatest common factor of the terms in the polynomial"

    14X^2 + 8X +72 is one of the many i have to solve. what do i do? where do i start?

    supposedly i have to multiply 14 and 72, which gives me 1008, then find two numbers that multiply to get 1008, but add to get 8.

    another kid in my class told me to bring out a 2, but then wtf do i do then?

    any help is appreciated.
    upgrade fund: $145
  • Target Practice
    irc.zirc.org:6667 = chat!
    • Nov 2003
    • 3180

    #2
    Go back in the book, and read the examples. Read the section. See how it is explained in the book, and see how the examples are done. Do this before asking for help.


    "Every normal man must be tempted at times to spit on his hands, hoist the black flag, and begin slitting throats." --Henry Louis Mencken.

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    • wanna-b-ballin'
      Pump Player
      • Jan 2005
      • 1380

      #3
      thats the thing. i did.

      all the examples dont really relate.

      the example is AX^2 + BX + C
      all the other examples have C^2

      when C is squared, it makes it easier. but it isn't. so i dont know what to do.
      upgrade fund: $145

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      • tropical_fishy
        KART
        • Oct 2004
        • 1017

        #4
        Originally posted by wanna-b-ballin'
        alright, so my math teacher just assigned me some crap, and did a real crappy job at giving us notes about it. looking in my book didn't really help me. so i came here.

        "find the greatest common factor of the terms in the polynomial"

        14X^2 + 8X +72 is one of the many i have to solve. what do i do? where do i start?

        supposedly i have to multiply 14 and 72, which gives me 1008, then find two numbers that multiply to get 1008, but add to get 8.

        another kid in my class told me to bring out a 2, but then wtf do i do then?

        any help is appreciated.
        There are no real factors in that equation. So you either wrote it down wrong here, or you're going about solving the problem the wrong way. If you use the quadratic formula you can pretty easily see that 8^2 < 4(14)(72).

        Do what TP said. If you still need help, I'll be around on AIM.

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        • MayAMonkeyBeYourPinata
          Another One Bites The Dust
          • Feb 2003
          • 2246

          #5
          Either use the quad formula, or factoring is basically just guess and check
          Love Will Tear Us Apart

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          • nippinout
            FUSP
            • Jan 2002
            • 1231

            #6
            (X^0.5)^2 = X

            Every real number can be rewritten into exponential form.

            In the case of positive numbers, the square of its square-root. Or the square-root of its square.

            I'm a mathemagician by trade.

            By the way, that's a horribly written problem.

            You only have an X in two of the three terms (Excluding X^0, which equals 1. It may help to think of the term without an X as having X^0). That is obviously not a common term. Do you remember how to factor a number? Factor the coefficients, and the greatest common factor is the solution. Well, as far as I am understanding the problem.
            BAM!
            TNS2K2's Viagra Adventure!

            Comment

            • Target Practice
              irc.zirc.org:6667 = chat!
              • Nov 2003
              • 3180

              #7
              Originally posted by nippinout
              By the way, that's a horribly written problem.
              Well, most textbook problems are.


              "Every normal man must be tempted at times to spit on his hands, hoist the black flag, and begin slitting throats." --Henry Louis Mencken.

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              • tropical_fishy
                KART
                • Oct 2004
                • 1017

                #8
                Originally posted by nippinout
                (X^0.5)^2 = X

                Every real number can be rewritten into exponential form.

                In the case of positive numbers, the square of its square-root. Or the square-root of its square.

                I'm a mathemagician by trade.

                By the way, that's a horribly written problem.

                You only have an X in two of the three terms (Excluding X^0, which equals 1. It may help to think of the term without an X as having X^0). That is obviously not a common term. Do you remember how to factor a number? Factor the coefficients, and the greatest common factor is the solution. Well, as far as I am understanding the problem.
                You can't factor that problem into real numbers though, only imaginary ones. b^2 - 4ac is a negative number, and thus the solution to the radical is imaginary.

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                • nippinout
                  FUSP
                  • Jan 2002
                  • 1231

                  #9
                  Originally posted by tropical_fishy
                  You can't factor that problem into real numbers though, only imaginary ones. b^2 - 4ac is a negative number, and thus the solution to the radical is imaginary.

                  Again, this is a horribly written problem. From the looks of it, this is an expression. An expression of incompetence and irrelevance.

                  You can factor the expression by pulling out common terms. Distributive property is very strong kung-fu.
                  BAM!
                  TNS2K2's Viagra Adventure!

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                  • tropical_fishy
                    KART
                    • Oct 2004
                    • 1017

                    #10
                    Originally posted by nippinout
                    Again, this is a horribly written problem. From the looks of it, this is an expression. An expression of incompetence and irrelevance.
                    That sounds like my precalc teacher!

                    Comment

                    • Lohman446
                      Useful posts: 7
                      • Jun 2003
                      • 9315

                      #11
                      Originally posted by wanna-b-ballin'
                      alright, so my math teacher just assigned me some crap, and did a real crappy job at giving us notes about it. looking in my book didn't really help me. so i came here.

                      "find the greatest common factor of the terms in the polynomial"

                      14X^2 + 8X +72 is one of the many i have to solve. what do i do? where do i start?

                      supposedly i have to multiply 14 and 72, which gives me 1008, then find two numbers that multiply to get 1008, but add to get 8.

                      another kid in my class told me to bring out a 2, but then wtf do i do then?

                      any help is appreciated.
                      You start with what is on the other side of that = sign.... You can plug in any number for X and have a valid equation, the answer would be different but, since you have no answer now
                      "Unless someone like you cares a whole awful lot, nothing is going to get better. Its not" - Dr Suess

                      Comment

                      • CKY_Alliance
                        Team Deranged
                        • Jan 2005
                        • 1695

                        #12
                        Originally posted by wanna-b-ballin'
                        alright, so my math teacher just assigned me some crap, and did a real crappy job at giving us notes about it. looking in my book didn't really help me. so i came here.

                        "find the greatest common factor of the terms in the polynomial"

                        14X^2 + 8X +72 is one of the many i have to solve. what do i do? where do i start?

                        supposedly i have to multiply 14 and 72, which gives me 1008, then find two numbers that multiply to get 1008, but add to get 8.

                        another kid in my class told me to bring out a 2, but then wtf do i do then?

                        any help is appreciated.
                        well i dont know what the ^ is about but without that i would do guess and check get all the factors for 2 and 72 then find the ones that add or subtract to equal 8 and you would be adding since the signs are the same,well i just tried to figure it out but idk becasue that extra 2 so yea i guess my input is useless

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                        • wanna-b-ballin'
                          Pump Player
                          • Jan 2005
                          • 1380

                          #13
                          i kinda figured out what it wanted late last night.

                          as for doing something with whats on the other side of the =, there is no = in that equasion. i'd assume it equals zero.

                          and the ^ sign . 26^2 would be 26 squared. or 26^3 would be 26 cubed.
                          upgrade fund: $145

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