How much energy is stored in HPA tank?

[askman]

I have to admit that It is bit confusing the way I wrote it.

pound of force is one pound of mass multiplied by gravity.

PSI is pound force per square inch. multiply it by volume (cubic inch), you end up with inch-pound. You can covert the inch-pound to foot-pound by dividing it by 12 (12inch per foot)


thus 68 cubic tank with 4500 psi have 25500 foot pound of energy. foot-pound-force is equal to 1.35582 joule. Thus 25500 foot pound is equavalent to 34573 joules of energy.

1 mole(227gm) of nitroglycerine have about 300k joule of energy, thus our tank has same energy as about 25gm of nitroglycerine. enough to blow your arm off.

hope this clears it up...

[hitech]

Originally posted by askman
...thus our tank has same energy as about 25gm of nitroglycerine.

Any idea how much nitroglycerine is in an average stick of dynamite?

[Rynoboy06]

Originally posted by Doc Nickel


-It could be argued instead, that you don't have enough.

Doc.

Go Doc!

[FutureMagOwner]

Originally posted by askman
25500 foot lb, assuming that you are 255lb wil lift you up 100ft or 10 stories.

so the moral of this story is treat tanks with respect or eat alot of fastfood and only get shot up 10 feet instead lol

[xmetal2001]

Originally posted by 2k1angel
In short it could rip your arm off.

It would rip off alot more than your arm.

Lets put it this way -- a exploding scuba tank can send an 18 wheeler into the air...they arent THAT much smaller.

Dont expect to be able to get away with losing an arm if your tank actually explodes.

But the idea behind fiber wrapping is basically to keep your tank from exploding and instead it would hopefully stay in one piece while the pressure escapes through the rupture in the tank.

Edit: WOW, weird, i just posted this a few seconds ago and according to the AO clock the post after mine hasn't even happened yet. Its 12:10 and it was made at 12:30 so it shows up after mine. Nifty yet weird.

[AcemanPB]

34573 joules? I wasn't expecting THAT much energy, wow. Well I was wondering if it's possible to find the least amount of energy required to get a paintball at 300fps (assuming no friction, etc). Now I'm curious how much of that energy is actually "wasted" .

[askman]

in ideal condition

34573 joules per tank, assuming that we get 1000-1700 round per tank it takes about 20-35 joule per shot. In reality, we can only use the pressure down to 600psi for mags and 2-300 for even the low pressure markers, so potential energy is less, meaning it probably is more like 20-30 joule.

In 100% efficient condition, assuming 3gm paintball, 30cm barrel, 300fps(84m/s),

d=.5*a*t*t
v=at
.3=.5a*t*t
84=a*t


.3=.5(84)*t :t=.00714sec, a=11765m/s^2 (about 1200g, wow, more than I thought)

f=m*a =.003*11765=35.3 newtons
e=f*d= 35.3*.3= 10.6 Joules per shot

Of course, simpler way is if we use Kinetic energy formula: ke=.5*m*v*v

ke=.5(.003)84*84=10.58 joules

either way, same answer.
So our marker is about 30-50% efficient. so maximum we can get is about 3000 shots even in perfect condition

[pbzmag]

After reading all those formulas, my head started to hurt! Even Einstien is going "WHAT"!!!

pbzmag